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Question
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 - 4x + 1 = 0
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Solution
x2 - 4x + 1 = 0
Here, a = 1, b = -4 and c = 1
D = b2 - 4ac
⇒ 16 - 4 x 1 x 1
⇒ 16 - 4
= 12 > 0
The given equation has real roots.
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