Question

With the help of the flow chart given below solve the equation \[x^2 + 2\sqrt{3}x + 3 = 0\] using the formula.

Answer 1

Comparing `x^2 + 2sqrt3x + 3 = 0` with ax² + bx + c = 0

we get a = 1, b = 2`sqrt3` and c = 3 

b² - 4ac = `(2sqrt3)^2- 4xx1xx3`

= 12 - 12

= 0 

Formula to solve a quadratic equation will be 

x = `(- b±sqrt(b^2 - 4ac))/(2a)`

⇒ x = `(-2sqrt3±sqrt(0))/(2xx1)`

= `(-2sqrt3)/2`

= `-sqrt3`

Thus, `x = -sqrt3, -sqrt3`