Advertisements
Advertisements
Question
Will the angular momentum of a planet be conserved? Justify your answer.
Advertisements
Solution
The torque experienced by the Earth due to the gravitational force of the Sun is given by,
`vecτ = vec"r" xx vec"F" = vec"r" xx (-("GM"_"S""M"_"E")/"r"^2 hat"r") = 0`
Since `vec"r" = "r", hat"r", (hat"r" xx hat"r") = 0`
So `vecτ = ("d" vec"L")/"dt" = 0`
It implies that angular momentum `vec"L"` is a constant vector. Hence L is conserved.
APPEARS IN
RELATED QUESTIONS
The magnitude of the Sun’s gravitational field as experienced by Earth is
Is potential energy the property of a single object? Justify.
Define gravitational potential.
What is the difference between gravitational potential and gravitational potential energy?
Derive the expression for gravitational potential energy.
If the Earth’s pull on the Moon suddenly disappears, what will happen to the Moon?
Two bodies of masses m and 4m are placed at a distance of r. Calculate the gravitational potential at a point on the line joining them where the gravitational field is zero.
Calculate the gravitational field at point O due to three masses m1, m2 and m3 whose positions are given by the following figure. If the masses m1 and m2 are equal what is the change in a gravitational field at the point O?

What is the gravitational potential energy of the Earth and Sun? The Earth to Sun distance is around 150 million km. The mass of the Earth is 5.9 × 1024 kg and the mass of the Sun is 1.9 × 1030 kg.
Earth revolves around the Sun at 30 km s−1. Calculate the kinetic energy of the Earth. In the previous example, you calculated the potential energy of the Earth. What is the total energy of the Earth in that case? Is the total energy positive? Give reasons.
