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Question
Why we need a 5 A fuse for an electric iron which consumes 1 kW power at 220 V?
Numerical
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Solution
We need a fuse of 5A for an electric iron which consumes 1 kW power at 220 V. It is because:
Given P = 1000 W, V = 220 V
As we know, P = V × t
Or I = `"P"/"V"`
= `1000/(220"V")`
= 4.5 A
Hence, the fuse should be of 5 A.
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