Advertisements
Advertisements
Question
Why is temperature co-efficient of resistance negative for semiconductor?
Advertisements
Solution
With the increase in temperature, the concentration of charge carriers (electrons and holes) increases. As more charge carriers are made available, the conductivity of a pure semiconductor increases i.e. resistivity of a pure semiconductor decreases with the rise in temperature i.e. semiconductors have a negative temperature coefficient of resistance.
APPEARS IN
RELATED QUESTIONS
Doping a semiconductor result in
What do you mean by doping?
Distinguish between intrinsic and extrinsic semiconductors.
Why can’t we interchange the emitter and collector even though they are made up of the same type of semiconductor material?
Elucidate the formation of n-type extrinsic semiconductors.
On doping an intrinsic semiconductor with a group V element, free electrons in the conduction band are the majority charge carriers and the resulting semiconductor has a net
The electron concentration in an n-type semiconductor is the same as the hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
The electron concentration in an n-type semiconductor is the same as the hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
The electron concentration in an n-type semiconductor is the same as the hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
