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Why are secondary maxima much weaker than the central maximum?

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Question

Why are secondary maxima much weaker than the central maximum?

Options

  • The secondary sources within the slit cease to be in phase

  • All wavelets arrive in phase at each secondary maximum

  • A significant portion of the slit still cancels out

  • All path differences are zero at each secondary maximum

MCQ
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Solution

At a secondary maximum, a significant portion of the slit still cancels out. Consequently, its intensity is much lower than that of the central maximum.

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