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Question
Which trigonometric substitution is suitable for \[a^2-x^2\] and \[\sqrt{a^2-x^2}\]?
Options
\[x=a\sin\theta\]
\[x=a\tan\theta\]
\[x=a\cos\theta\]
\[x=a\sec\theta\]
MCQ
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Solution
For \[a^2-x^2\] or \[\sqrt{a^2-x^2}\], use \[x=a\sin\theta\]. This converts the expression using the identity involving \[1-\sin^2\theta\].
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