Question

Which term of the G.P. $$\sqrt{3}, 3\sqrt{3}, 9\sqrt{3}, .......$$ is $$729\sqrt{3}$$?

Options

• 7th

• 6th

• 9th

• 8th

Answer 1

7th

Explanation:

The first term is $$\sqrt3$$ and the common ratio is $$3$$. Since $$729 = 3^6$$, the term is $$T_7 = \sqrt3\times3^6 = 729\sqrt3$$.