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Which term of the G.P. 5, 10, 20, 40, ..... is 640?

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Question

Which term of the G.P. 5, 10, 20, 40, ..... is 640?

Sum
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Solution

Here the first term $$a = 5$$ and the common ratio $$r = \frac{10}{5} = 2$$.

Let the 640 be the nth term. Then,

$$T_n = ar^{n - 1} \Rightarrow 5 \times 2^{n - 1} = 640$$

$$2^{n - 1} = \frac{640}{5} = 128 = 2^7$$

$$n - 1 = 7 \Rightarrow n = 8$$

Hence, 640 is the 8th term of the given G.P.

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Chapter 11: Geometric Progression - EXERCISE 11A [Page 177]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 11 Geometric Progression
EXERCISE 11A | Q 8. | Page 177
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