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Question
Which term of the A.P. –2, –7, –12,..... will be –77? Find the sum of this A.P. upto the term –77.
Sum
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Solution
Given: AP: –2, –7, –12,.....
First term a = –2, common difference d = –7 – (–2) = –5.
Step-wise calculation:
1. Find n such that Tn = –77:
Tn = a + (n – 1)d – 77
= –2 + (n – 1)(–5) – 77 + 2
= (n – 1)(–5) – 75
= –5(n – 1)
n – 1 = 15
⇒ n = 16
2. Sum up to the 16th term (Sn):
`S_n = n/2 [2a + (n - 1)d]`
`S_16 = 16/2 [2(-2) + (16 - 1)(-5)]`
= 8[–4 + 15(–5)]
= 8[–4 – 75]
= 8(–79)
= –632
The term –77 is the 16th term of the AP and the sum of the AP up to –77 is –632.
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