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Question
Which substitution is appropriate for \[\sqrt{\frac{\mathrm{a}-x}{\mathrm{a}+x}}\] or \[\sqrt{\frac{\mathrm{a}+x}{\mathrm{a}-x}}\]?
Options
\[x=a\sec\theta\]
\[x=a\tan^2\theta\]
\[x=a\cos 2\theta\]
\[x=a\sin\theta\]
MCQ
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Solution
For ratios involving \[\mathrm{a}-x\] and \[\mathrm{a}+x\], use \[x=a\cos 2\theta\]. The double-angle expression simplifies both numerator and denominator.
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