Question

Which sequence expresses the photon relation used to obtain the de Broglie relation?

Options

• \[p=\frac{E}{c}=\frac{h}{\nu c}=\frac{\lambda}{h}\]

• \[p=\frac{c}{E}=\frac{c}{h\nu}=\frac{\lambda}{h}\]

• \[p=\frac{E}{c}=\frac{h\nu}{c}=\frac{h}{\lambda}\]

• \[p=Ec=h\nu c=h\lambda\]

Answer 1

The photon relation connects momentum, energy, frequency, and wavelength as \[p=\frac{E}{c}=\frac{h\nu}{c}=\frac{h}{\lambda}\]. Rearranging its final equality gives the de Broglie relation.