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Which relationship gives the number of photons emitted per second by a laser of power \[P\] when each photon has energy \[E\]?

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Question

Which relationship gives the number of photons emitted per second by a laser of power \[P\] when each photon has energy \[E\]?

Options

  • \[P=N+E\quad\Rightarrow\quad N=P-E\]

  • \[P=NE\quad\Rightarrow\quad N=\frac{E}{P}\]

  • \[P=\frac{N}{E}\quad\Rightarrow\quad N=PE\]

  • \[P=NE\quad\Rightarrow\quad N=\frac{P}{E}\]

MCQ
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Solution

Power is the total photon energy emitted per second, so \[P=NE\]. Dividing power by the energy of one photon gives \[N=\frac{P}{E}\], the number emitted per second.

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