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Question
Which relation expresses that the voltage across the capacitor equals the applied voltage?
Options
\[qC=v_m\sin\omega t\]
\[\frac{q}{C}=v_m\sin\omega t\]
\[\frac{q}{C}=v_m\cos\omega t\]
\[\frac{C}{q}=v_m\sin\omega t\]
MCQ
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Solution
The voltage across a capacitor is \[\frac{q}{C}\]. Equating it to the applied voltage gives \[\frac{q}{C}=v_m\sin\omega t\].
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