Question

Which of the following relations is incorrect?

Options

• R = `1/"k"("l"/"a")`

• G = `"k"("a"/"l")`

• G = `"k"("l"/"a")`

• ∧_m = `"k"/"c"`

Answer 1

G = `bb("k"("l"/"a"))`

Explanation:

The inverse of resistance, R, is called conductance, G, and we have the relation:

G = `1/"R" = "A"/(ρ"l") = κ"A"/"l"`