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Question
Which of the following complexes show linkage isomerism?
(i) \[\ce{[Co(NH3)5 (NO2)]^{2+}}\]
(ii) \[\ce{Co(H2O)5 CO]^{3+}}\]
(iii) \[\ce{[Cr(NH3)5 SCN]^{2+}}\]
(iv) \[\ce{Fe(en)2 Cl2]^+}\]
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Solution
(i) \[\ce{[Co(NH3)5 (NO2)]^{2+}}\]
(iii) \[\ce{[Cr(NH3)5 SCN]^{2+}}\]
Explanation:
In the given complexes at \[\ce{[Co(NH3)5 (NO2)]^{2+}}\] and \[\ce{[Cr(NH3)5 SCN]^{2+}}\] the central metal atom (i.e. Co and Cr respectively) are bonded with ligands \[\ce{NO2}\] and \[\ce{SCN}\] separately. These ligands are ambidentate ligands and can link themselves with the central atom in two different ways exhibiting linkage isomerism (as mentioned below) -
In \[\ce{NO2}\] linkage isomerism arises in a coordination compound containing ambidentate ligand. A simple example is provided by complexes containing the thiocyanate ligands. \[\ce{NCS^-}\], which may bind through the nitrogen to give \[\ce{M-NCS}\] or through sulpur to give \[\ce{M-SCN}\].
In \[\ce{NO2}\] such behaviour in the complex \[\ce{[Co(NH3)5NO2]^{+2}}\], obtained in the red form, when nitrite ligand is bound through oxygen \[\ce{(ONO)}\], and in yellow form, when the nitrite ligand is bound through nitrogen (–NO2)
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| A. \[\ce{[Co(NH3)4 Cl2]^+}\] | 1. optical |
| B. \[\ce{cis-[Co(en)2 Cl2]^+}\] | 2. ionisation |
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| 5. linkage |
Assertion: Linkage isomerism arises in coordination compounds containing ambidentate ligand.
Reason: Ambidentate ligand has two different donor atoms
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