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Question
Which microscopic relation for resistivity is given in terms of conductivity, electron mass, free-electron number density, electronic charge, and average relaxation time?
Options
\[\rho=\frac{1}{\sigma}=\frac{m}{ne^2\tau}\]
\[\rho=\sigma=\frac{ne^2\tau}{m}\]
\[\rho=\frac{\tau}{mne^2}\]
\[\rho=\frac{mne^2}{\tau}\]
MCQ
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Solution
The microscopic relation is \(\rho=\frac{1}{\sigma}=\frac{m}{ne^2\tau}\). It relates resistivity to conductivity and to properties of electrons in the material.
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