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Question
Which identity is used for \(\cos^2 x\)?
Options
\(\sin 3x = 3\sin x - 4\sin^3 x\)
\(\cos^2 x = \frac{1-\cos 2x}{2}\)
\(\cos 2x = 2\cos^2 x - 1\)
\(\sin A\cos B = \frac{1}{2}[\sin(A+B)+\sin(A-B)]\)
MCQ
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Solution
The identity \(\cos 2x = 2\cos^2 x - 1\) directly contains \(\cos^2 x\). Rearranging it gives the useful even-power form.
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