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Question
Which formula correctly gives the acceleration due to gravity using a simple pendulum, where L is the length and T is the time period?
Options
g = \[\frac {2πL}{T^2}\]
g = \[\frac {4π^2L}{T^2}\]
g = \[\frac {4πL}{T}\]
g = \[\frac {π^2L}{T^2}\]
MCQ
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Solution
g = \[\frac {4π^2L}{T^2}\]
Explanation:
This formula is derived from the time period equation T = 2π\[\sqrt {L/g}\]. Squaring and rearranging gives g = \[\frac {4π^2L}{T^2}\], which allows us to experimentally determine gravitational acceleration by measuring L and T.
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Simple Pendulum
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