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Question
Which of the following number is not perfect cubes?
216
Sum
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Solution
On factorising 216 into prime factors, we get:
\[216 = 2 \times 2 \times 2 \times 3 \times 3 \times 3\]
On grouping the factors in triples of equal factors, we get:
\[216 = \left\{ 2 \times 2 \times 2 \right\} \times \left\{ 3 \times 3 \times 3 \right\}\]
It is evident that the prime factors of 216 can be grouped into triples of equal factors and no factor is left over. Therefore, 216 is a perfect cube.
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