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Question
Which expression gives the drift velocity in terms of electric field \[E\], relaxation time \[\tau\], electronic charge \[e\], and electron mass \[m\]?
Options
\[v_d=-\frac{eE}{m\tau}\]
\[v_d=\frac{I}{A}\]
\[v_d=-\frac{eE\tau}{m}\]
\[v_d=\frac{ne^2\tau}{m}\]
MCQ
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Solution
The drift velocity is \[v_d=-\frac{eE\tau}{m}\]. The negative sign indicates that electron drift is opposite to the electric field.
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