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Question
Which derivative and condition are correct for \[\sec^{-1}x\]?
Options
\[\frac{d}{dx}(\sec^{-1}x)=\frac{1}{|x|\sqrt{x^2-1}},\quad |x|>1\]
\[\frac{d}{dx}(\sec^{-1}x)=\frac{1}{1+x^2},\quad x\in\mathbb{R}\]
\[\frac{d}{dx}(\sec^{-1}x)=\frac{1}{\sqrt{1-x^2}},\quad |x|<1\]
\[\frac{d}{dx}(\sec^{-1}x)=-\frac{1}{|x|\sqrt{x^2-1}},\quad |x|>1\]
MCQ
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Solution
For \[\sec^{-1}x\], the denominator involves \[|x|\sqrt{x^2-1}\]. The required condition is \[|x|>1\], and the derivative is positive.
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