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Question
Which among the following is correct for electrolysis of brine solution?
Options
O2 gas is liberated at cathode
Sodium metal is collected at anode
H2 gas is liberated at cathode
Cl2 gas is liberated at cathode
MCQ
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Solution
H2 gas is liberated at cathode
Explanation:
In electrolysis of brine solution, H2 gas is liberated at cathode. The solution contains four ions Na+, Cl⊖, H+ and OH ions. There occurs a race amongst them for their discharge at their respective electrodes.
Following electrode reactions are possible:
Cathode- \[\ce{2H2O(l) + 2e- -> H2(g) + 2\bar{\text{O}}H(aq)}\]
Anode- \[\ce{2Cl- (aq) -> Cl2(g) + 2e-}\]
In this electrolysis, H2 at cathode and Cl2 at anode are given off.
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Chlorine and Compounds of Chlorine
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