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When the electric field direction is opposite to the area vector (θ = 180°), what is the flux?

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Question

When the electric field direction is opposite to the area vector (θ = 180°), what is the flux?

Options

  • \[\Phi = 0\]

  • \[\Phi = -EA\]

  • \[\Phi = EA/2\]

  • \[\Phi = EA\]

MCQ
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Solution

When θ = 180°, \[\cos(180°) = -1\], so \[\Phi = EA \cos(180°) = -EA\]. This represents the maximum negative flux, indicating that field lines enter the surface opposite to the direction of the chosen outward normal.

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