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Question
When the electric field direction is opposite to the area vector (θ = 180°), what is the flux?
Options
\[\Phi = 0\]
\[\Phi = -EA\]
\[\Phi = EA/2\]
\[\Phi = EA\]
MCQ
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Solution
When θ = 180°, \[\cos(180°) = -1\], so \[\Phi = EA \cos(180°) = -EA\]. This represents the maximum negative flux, indicating that field lines enter the surface opposite to the direction of the chosen outward normal.
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