Advertisements
Advertisements
Question
When orange solution containing \[\ce{Cr2O^{2-}7}\] ion is treated with an alkali, a yellow solution is formed and when \[\ce{H^+}\] ions are added to yellow solution, an orange solution is obtained. Explain why does this happen?
Advertisements
Solution
This is due to the interconversion of dichromate (orange) to chromate ion (yellow).
\[\ce{\underset{\underset{(Orange)}{Dichromate}}{Cr2O^{2-}7} ⇌[OH^-][H^+] \underset{\underset{(Yellow)}{Chromate}}{CrO^{2-}4}}\]
APPEARS IN
RELATED QUESTIONS
Complete the following equations:

Complete the following chemical equation
8MnO4- + 3S2O32- + H2O →
Complete the following equation :
`2MnO_4^(-)+6H^++5NO_2^(-)rarr`
Complete the following equations : MnO4- + 4H+ + 3e- →
Describe the preparation of potassium permanganate. How does the acidified permanganate solution react with iron (II) ions? Write the ionic equation for the reaction.
Give an example and suggest a reason for the following feature of the transition metal chemistry:
The lowest oxide of transition metal is basic, the highest is amphoteric/acidic.
Complete the following equations:
`2MnO_4^(-)+16H^++5S^(2-)rarr`
Complete the following chemical equations :
Cu + H2SO4(conc.) →
Account for the following :
Manganese shows maximum number of oxidation states in 3d series.
Why \[\ce{HCl}\] should not be used for potassium permanganate titrations?
Potassium dichromate when heated with concentrated sulphuric acid and a soluble chloride, gives brown-red vapours of ______.
Complete the following ionic equation:
\[\ce{Cr2O^{2-}7 + 2OH^- ->}\]
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
