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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

When orange solution containing CrX2OX72− ion is treated with an alkali, a yellow solution is formed and when HX+ ions are added to yellow solution, an orange solution is obtained. Explain

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प्रश्न

When orange solution containing \[\ce{Cr2O^{2-}7}\] ion is treated with an alkali, a yellow solution is formed and when \[\ce{H^+}\] ions are added to yellow solution, an orange solution is obtained. Explain why does this happen?

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उत्तर

This is due to the interconversion of dichromate (orange) to chromate ion (yellow). 

\[\ce{\underset{\underset{(Orange)}{Dichromate}}{Cr2O^{2-}7} ⇌[OH^-][H^+] \underset{\underset{(Yellow)}{Chromate}}{CrO^{2-}4}}\]

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पाठ 8: The d-and f-Block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १११]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 8 The d-and f-Block Elements
Multiple Choice Questions (Type - I) | Q 45 | पृष्ठ १११

संबंधित प्रश्‍न

Complete the following equation :

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(a) \[\ce{Cu^{+} -> Cu^{2+} + Cu}\]

(b) \[\ce{3MnO^{-}4 + 4H^{+} -> 2MnO^{-}4 + MnO2 + 2H2O}\]

(c) \[\ce{2KMnO4 -> K2MnO4 + MnO2 + O2}\]

(d) \[\ce{2MnO^{-}4 + 3Mn^{2+} + 2H2O -> 5MnO2 + 4H^{+}}\]


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(i) \[\ce{KMnO4}\]

(ii) \[\ce{Ce(SO4)2}\]

(iii) \[\ce{TiCl}\]

(iv) \[\ce{Cu2 Cl2}\]


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