Advertisements
Advertisements
Question
When concentrated sulphuric acid was added to an unknown salt present in a test tube a brown gas (A) was evolved. This gas intensified when copper turnings were added to this test tube. On cooling, the gas (A) changed into a colourless solid (B).
1) Identify (A) and (B).
2) Write the structures of (A) and (B).
3) Why does gas (A) change to solid on cooling?
Advertisements
Solution
1) A = NO2 ; B = N2O4
2)

3) It converts into solid because of NO2 form dimer i.e N2O4 at low temperature.
APPEARS IN
RELATED QUESTIONS
What happens when dilute sulphuric acid is treated with Fe
What is the action of concentrated sulphuric acid on potassium chlorate?
Give balanced chemical equations for Sulphuric acid is treated with hydrogen sulphide
Write chemical reactions for different steps in the manufacture of sulphuric acid by lead chamber process. Draw the structure of phosphorous pentachloride
Complete and balance the following equations:
S+H2SO4(conc.) →
Write a balanced chemical equation for the following reaction:
Sulphuric acid is treated with phosphorous.
Write the reaction of conc. H2SO4 with sugar.
Identify the products formed when conc. sulfuric acid reacts with calcium fluoride.
The molecular formula of oleum is ____________.
Which of the following statements are correct?
(i) S – S bond is present in \[\ce{H2S2O6}\].
(ii) In peroxosulphuric acid \[\ce{(H2SO5)}\] sulphur is in +6 oxidation state.
(iii) Iron powder along with \[\ce{Al2O3}\] and \[\ce{K2O}\] is used as a catalyst in the preparation of \[\ce{NH3}\] by Haber’s process.
(iv) Change in enthalpy is positive for the preparation of \[\ce{SO3}\] by catalytic oxidation of \[\ce{SO2}\].
