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प्रश्न
When concentrated sulphuric acid was added to an unknown salt present in a test tube a brown gas (A) was evolved. This gas intensified when copper turnings were added to this test tube. On cooling, the gas (A) changed into a colourless solid (B).
1) Identify (A) and (B).
2) Write the structures of (A) and (B).
3) Why does gas (A) change to solid on cooling?
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उत्तर
1) A = NO2 ; B = N2O4
2)
3) It converts into solid because of NO2 form dimer i.e N2O4 at low temperature.
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(i) S – S bond is present in \[\ce{H2S2O6}\].
(ii) In peroxosulphuric acid \[\ce{(H2SO5)}\] sulphur is in +6 oxidation state.
(iii) Iron powder along with \[\ce{Al2O3}\] and \[\ce{K2O}\] is used as a catalyst in the preparation of \[\ce{NH3}\] by Haber’s process.
(iv) Change in enthalpy is positive for the preparation of \[\ce{SO3}\] by catalytic oxidation of \[\ce{SO2}\].
The oxidation number of sulphur in Na2S4O6 is:-
