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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Why is Ka2<<Ka1Ka2<<Ka1 for H2SO4H2SO4 in water?

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प्रश्न

Why is `K_(a_2) "<<" K_(a_1)` for `H_2SO_4` in water?

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उत्तर

`H_2SO_(4(aq)) + H_2O_(l)  -> H_3O_(aq)^(+) + HSO_(4(aq))^(-); K_(a1) > 10`

`HSO_(4(aq))^(-) + H_2O_(l) -> H_3O_(aq)^(+) + SO_(4(aq))^(-); K_(a_2) = 1.2 xx10^(-2)`

It can be noticed that `K_(a_2) ">>" K_(a_1)`

This is because a neutral H2SO4 has a much higher tendency to lose a proton than the negatively charged `HSO_4^(-)`. Thus, the former is a much stronger acid than the latter.

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