Question

What will be the order of reaction if the plot of log₁₀[A] vs time is a straight line with a negative slope?

Answer 1

If the plot of log_⁡10[A] versus time (t) is a straight line with a negative slope, then the reaction is of first order.

For a first-order reaction, the integrated rate law is

`log_10[A] = log_10[A]_n - k/2.303 t`

This is a linear equation of the form

y = c − mt

Where:

y = log⁡₁₀[A],

t is time,

The slope `m = k/2.303` (positive constant),

So the slope of the graph is negative (because of the minus sign).