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Question
What will be the correct order for the wavelengths of absorption in the visible region for the following?
[Ni(NO2)6]4−, [Ni(NH3)6]2+, [Ni(H2O)6]2+
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Solution
The order of ligands present in the hybrid compounds given in the spectrochemical series is as follows:
\[\ce{H2O < NH3 < NO^-_2}\]
Therefore, the order of wavelength of absorbed light will be as follows –
[Ni(H2O)6]2+ < [Ni(NH3)6]2+ < [Ni(NO2)6]4−
Since the observed wavelengths are complementary to the absorbed wavelengths, the wavelengths of absorbed light will be E = `(hc)/λ` in the opposite order i.e. [Ni(NO2)6]4− < [Ni(NH3)6]2+ < [ Ni(H2O)6]2+.
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