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What Weight of Sulphuric Acid Will Be Required to Dissolve 3g of Magnesium Carbonate?

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Question

What weight of sulphuric acid will be required to dissolve 3g of magnesium carbonate?
[Mg = 24, C =12, 0 = 16 ]
MgCO3 + H2SO4 → MgSO4 + H2O+ CO2

Sum
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Solution

Molecular formula of MgCO3 is = 84
Molecular formula of H2SO4 = 98
Now if, 84g of MgCO3 requires = 98g of H2SO4.
3g of MgC03 will require = 98 x 3/84 = 3.5g
So, 3.5g of sulphuric acid will be required to dissolve 3g of magnesium carbonate.

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Chapter 5: Mole Concept and Stoichiometry - Exercise 2 [Page 116]

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Frank Chemistry Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Exercise 2 | Q 10 | Page 116

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