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Question
What weight of sulphuric acid will be required to dissolve 3g of magnesium carbonate?
[Mg = 24, C =12, 0 = 16 ]
MgCO3 + H2SO4 → MgSO4 + H2O+ CO2
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Solution
Molecular formula of MgCO3 is = 84
Molecular formula of H2SO4 = 98
Now if, 84g of MgCO3 requires = 98g of H2SO4.
3g of MgC03 will require = 98 x 3/84 = 3.5g
So, 3.5g of sulphuric acid will be required to dissolve 3g of magnesium carbonate.
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