English

Calculate the volume occupied at S.T.P. by 2 moles of SO2.

Advertisements
Advertisements

Question

Calculate the volume occupied at S.T.P. by 2 moles of SO2.

Numerical
Advertisements

Solution

1 mole of SO2 has volume = 22.4 litres

So, 2 moles will have = 22.4 x 2 = 44.8 litre

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Mole concept and Stoichiometry - EXERCISE-5B [Page 84]

APPEARS IN

S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5B | Q 10. (b) | Page 84

RELATED QUESTIONS

If a crop of wheat removes 20 Kg of nitrogen per hectare of soil, what mass of the fertilizer calcium nitrate,Ca(NO3)2 would be required to replace nitrogen in 10 hectare field? (N = 14, O = 16, Ca = 40)


A metal M, forms a volatile chloride containing 65.5% Chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride. [M = 56, Cl = 35.5]


Explain the term:

Vapour density


Calculate the relative molecular mass of:

Potassium chlorate


Calculate the relative molecular mass of:

CHCl3 


Calculate the number of hydrogen atoms in 0.1 mole of H2SO4.


What do you understand by the statement that ‘vapour density of carbon dioxide is 22’?


A gas cylinder filled with hydrogen holds 5 g of the gas. The same cylinder holds 85 g of gas X under the same temperature and pressure. Calculate the vapour density of gas X.


When heated, potassium permanganate decomposes according to the following equation :

\[\ce{2KMnO4 -> \underset{\text{solid residue}}{K2MnO4 + MnO2} + O2}\]

(a) Some potassium permanganate was heated in the test tube. After collecting one litre of oxygen at room temperature, it was found that the test tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g, calculate the relative molecular mass of oxygen.

(b) Given that the molecular mass of potassium permanganate is 158. What volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g of potassium permanganate? (Molar volume at room temperature is 24 litres)


67.2 litres of hydrogen combines with 44.8 litres of nitrogen to form ammonia under specific conditions as:

\[\ce{N2_{(g)} + 3H2_{(g)} -> 2NH3_{(g)}}\]

Calculate the volume of ammonia produced. What is the other substance, if any, that remains in the resultant mixture?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×