Question

What is the value of \[\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}\]

Answer 1

We have, 

`sin^2 θ+1/(1+tan^2θ)= sin^2θ+1/(sqc^2θ)` 

=` sin^2θ+(1/secθ)^2`  

=` sin^2 θ+cos^2θ` 

=` 1`