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What upper limit for the radius of the gold nucleus follows from the calculated distance of closest approach?

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Question

What upper limit for the radius of the gold nucleus follows from the calculated distance of closest approach?

Options

  • Exactly \[3.84\times10^{-16}\,\mathrm{m}\]

  • Greater than \[3.0\times10^{-14}\,\mathrm{m}\]

  • Exactly \[3.0\times10^{-14}\,\mathrm{m}\]

  • Less than \[3.0\times10^{-14}\,\mathrm{m}\]

MCQ
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Solution

The alpha particle reverses direction at a centre-to-centre distance of \[3.0\times10^{-14}\,\mathrm{m}\]. The gold nucleus’s radius must be less than this distance; the distance is not its exact radius.

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