Question

What possible output(s) from the given options will NOT be displayed when the following code is executed? Also, mention, for how many iterations the for loop in the given code will run?

import random
a = [1, 2, 3, 4, 5, 6]
for i in range (4) :
    j = random.randrange (i, 5)
    print(a[j],end='-')
print()

Options

• 3−4−5−4−

• 2−2−4−5−

• 4−3−3−5−

• 5−1−2−4−

Answer 1

5−1−2−4−

Explanation:

random.randrange(i,5) yields j in [i..4], so the second iteration (i=1) can only pick indices ≥1, it cannot produce index 0, therefore the sequence containing "1" in the second position (5-1-2-4-) is impossible.