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Question
What path difference produces a bright fringe?
Options
The angular fringe width, \[\alpha=\frac{\lambda}{d}\]
An odd multiple of half a wavelength, \[\Delta=\frac{(2m-1)\lambda}{2}\]
The fringe width, \[\beta=\frac{\lambda D}{d}\]
An integral multiple of wavelength, \[\Delta=n\lambda\]
MCQ
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Solution
Bright fringes result from constructive interference. This occurs when the path difference is an integral multiple of wavelength: \[\Delta=n\lambda\].
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