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Question
What number must be subtracted from the polynomial x3 − 6x2 + 2x so that (x – 1) is a factor of resulting polynomial?
Sum
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Solution
Let the number subtracted be k
f(x) = x3 − 6x2 + 2x − k
Let x – 1 = 0
x = 1
f(1) = 13 − 6(1)2 + 2(1) − k
= 1 − 6 + 2 − k
= −3 − k
Set the remainder f(1) equal to zero to find the value of k
f(1) = 0
−3 − k = 0
k = −3
∴ The number that must be subtracted is −3.
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