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Question
What number must be added to x3 + 5x2 − 6x so that the resulting polynomial is exactly divisible by (x – 2)?
Sum
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Solution
Let the number added be k
f(x) = x3 + 5x2 − 6x + k
Let x – 2 = 0
x = 2
f(2) = 23 + 5(2)2 − 6(2) + k
= 8 + 5(4) − 12 + k
= 8 + 20 − 12 + k
= 16 + k
Set the remainder f(2) equal to zero to find the value of k
f(2) = 0
16 + k = 0
k = −16
∴ The number that must be added to the polynomial so that the resulting polynomial is exactly divisible by (x – 2) is −16.
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