Question

What mass of N₂ will be required to produce 34.0 g of NH₃ by the reaction, \[\ce{N2 + 3H2 -> 2NH3}\]?

Options

• 28 g

• 14 g

• 12 g

• 17 g

Answer 1

28 g

Explanation:

\[\ce{N2 + 3H2 -> 2NH3}\]

According to the equation:

1 mole of N₂ = 28 g

2 moles of NH₃ = 2 × 17 = 34 g

Therefore, 28 g of N₂ is required to produce 34 g of NH₃.