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Question
What mass of Ca will contain the same number of atoms as are present in 3.2 g of S?
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Solution
3.2 g of S has number of atoms = `(6.02 xx10^23)/32 xx 3.2`
= 6.02 x 1023 atoms
So, 6.02 x 1023 atoms are present in Ca = 40 g
= `40/(6.02 xx 10^23) xx 6.02 xx 10^22`
= 4 g
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