Advertisements
Advertisements
प्रश्न
What mass of Ca will contain the same number of atoms as are present in 3.2 g of S?
Advertisements
उत्तर
3.2 g of S has number of atoms = `(6.02 xx10^23)/32 xx 3.2`
= 6.02 x 1023 atoms
So, 6.02 x 1023 atoms are present in Ca = 40 g
= `40/(6.02 xx 10^23) xx 6.02 xx 10^22`
= 4 g
संबंधित प्रश्न
One of the following elements has an atomicity of ‘one’. This element is :
Calculate the mole ratio of 240 g of calcium and 240 g of magnesium. (Ca = 40 u ; Mg = 24 u)
Fill in the blank.
One a.m.u. is the mass of ______ atom of C12.
Define the term:
Mole
How many grams of HCl are present in 0.1 mole of it?
How many grams of CO2 is present in 0.1 mole of it?
Calculate the mass of 0.1 mole of the following:
Mg
(Ca = 40, Na = 23, Mg = 24, S = 32, C = 12, Cl = 35.5, O = 16, H = 1)
Calculate the number of atoms in the following:
52 amu of He
Match the following.
| 1. | 8 g of O2 | - | 4 moles |
| 2. | 4 g of H2 | - | 0.25 moles |
| 3. | 52 g of He | - | 2 moles |
| 4. | 112 g of N2 | - | 0.5 moles |
| 5. | 35.5 g of Cl2 | - | 13 moles |
Cinnabar (HgS) is a prominent ore of mercury. How many grams of mercury are present in 225 g of pure HgS? Molar mass of Hg and S are 200.6 g mol–1 and 32 g mol–1 respectively.
