Advertisements
Advertisements
प्रश्न
What mass of Ca will contain the same number of atoms as are present in 3.2 g of S?
Advertisements
उत्तर
3.2 g of S has number of atoms = `(6.02 xx10^23)/32 xx 3.2`
= 6.02 x 1023 atoms
So, 6.02 x 1023 atoms are present in Ca = 40 g
= `40/(6.02 xx 10^23) xx 6.02 xx 10^22`
= 4 g
APPEARS IN
संबंधित प्रश्न
What is the mass of 10 moles of sodium sulphite (Na2SO3)?
- The percentage composition of a gas is:
Nitrogen 82.35%, Hydrogen 17.64%. - Find the empirical formula of the gas. [N = 14, H = 1]
How many moles of O2 are there in 1.20 × 1022 oxygen molecules ?
Prove the Following :
One mole of any gas contains th e same number of molecules.
Find the number of molecules in 73 g of HCl.
If phosphorus is considered to contain P4 molecules, then calculate the number of moles in 100g of phosphorus?
Correct the statement, if required.
The relative atomic mass of an element is the number of times one molecule of an element is heavier than `1/12` the mass of an atom of C12.
N2 + 3H2 → 2NH3
(The atomic mass of nitrogen is 14, and that of hydrogen is 1)
1 mole of nitrogen (______ g) +
3 moles of hydrogen (______ g) →
2 moles of ammonia (______ g)
How many grams are there in the following?
3 moles of chlorine molecule, Cl2.
Fill in the missing data in the Table
| Species Property | H2O | CO2 | Na atom | MgCl2 |
| No. of moles | 2 | - | - | 0.5 |
| No. of particles | - | 3.011×1023 | - | - |
| Mass | 36g | - | 115 g | - |
