Advertisements
Advertisements
Question
What is the quantity of hydrogen gas liberated when 46 g sodium reacts with excess ethanol?
Options
2.4 × 10-3 kg
2.0 × 10-3 kg
4.0 × 10-3 kg
2.4 × 10-2 kg
MCQ
Advertisements
Solution
2.0 × 10-3 kg
Explanation:
The reaction of ethanol with water:
\[\ce{2C2H5OH(l) + 2Na(s) -> 2C2H5\bar{\text{O}} Na+ + H2(g) \uparrow}\]
2 mole of Na (46 g) = 1 mole of H2
= 2 g = 2.0 × 10-3 kg
shaalaa.com
Nomenclature of Alcohols, Phenols and Ethers
Is there an error in this question or solution?
