Question

What is the quantity of hydrogen gas liberated when 46 g sodium reacts with excess ethanol?

विकल्प

• 2.4 × 10^-3 kg

• 2.0 × 10^-3 kg

• 4.0 × 10^-3 kg 

• 2.4 × 10^-2 kg

Answer 1

2.0 × 10^-3 kg 

Explanation:

The reaction of ethanol with water:

\[\ce{2C2H5OH(l) + 2Na(s) -> 2C2H5\bar{\text{O}} Na+ + H2(g) \uparrow}\]

2 mole of Na (46 g) = 1 mole of H₂

= 2 g = 2.0 × 10^-3 kg