Advertisements
Advertisements
Question
What is the motional EMF across a small element \[dr\] of a rotating rod?
Options
\[d\varepsilon=B\omega\,dr/r\]
\[d\varepsilon=Bv\,dr=B\omega r\,dr\]
\[d\varepsilon=B\omega R^2\,dr\]
\[d\varepsilon=Br\,dr/\omega\]
MCQ
Advertisements
Solution
Apply the motional emf formula to the small length \[dr\]: \[d\varepsilon=Bv\,dr\]. Since its velocity is \[v=\omega r\], this becomes \[d\varepsilon=B\omega r\,dr\].
shaalaa.com
Is there an error in this question or solution?
