Question

What is the magnitude of the position vector of \[P(3,4,0)\]?

Options

• \[5\] units

• \[7\] units

• \[25\] units

• \[0\] units

Answer 1

Using \[|\vec{OP}|=\sqrt{x^2+y^2+z^2}\], we get \[\sqrt{3^2+4^2+0^2}=\sqrt{25}\]. Therefore, the magnitude of the position vector is \[5\] units.