Advertisements
Advertisements
Question
What is the magnetic flux through one turn at time \[t\]?
Options
\[\Phi_B=BA\sin(\omega t)\]
\[\Phi_B=BA\cos(\omega t)\]
\[\Phi_B=BA\omega\sin(\omega t)\]
\[\Phi_B=NBA\cos(\omega t)\]
MCQ
Advertisements
Solution
Flux through one turn is \[\Phi_B=BA\cos(\omega t)\]. The cosine reflects the changing angle between the area vector and \[B\].
shaalaa.com
Is there an error in this question or solution?
