Question

What is the impedance of a series LCR circuit with \[R=3\,\Omega\], \[X_L=8\,\Omega\], and \[X_C=4\,\Omega\]?

Options

• \[Z=3\,\Omega\]

• \[Z=12\,\Omega\]

• \[Z=5\,\Omega\]

• \[Z=8\,\Omega\]

Answer 1

The impedance is \[Z=\sqrt{R^2+(X_L-X_C)^2}\]. Substituting the values gives \[Z=\sqrt{3^2+(8-4)^2}=5\,\Omega\].