Question

What is the effect of inserting a dielectric with \[K>1\] between the plates?

Options

• Capacitance increases to \[C=\frac{K\varepsilon_0 A}{d}\]

• Capacitance becomes \[C=\frac{d}{K\varepsilon_0 A}\]

• Capacitance decreases to \[C=\frac{\varepsilon_0 A}{Kd}\]

• Capacitance remains unchanged at \[C=\frac{\varepsilon_0 A}{d}\]

Answer 1

A dielectric with \[K>1\] increases capacitance by the factor \[K\]. The capacitance with the dielectric is \[C=\frac{K\varepsilon_0 A}{d}\].