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Question
What is the decrease in potential energy of charge \[\Delta Q\] moving through potential difference \[V\]?
Options
\[\Delta U_{\text{pot}} = -V\Delta Q\]
\[\Delta U_{\text{pot}} = I\Delta Q\]
\[\Delta U_{\text{pot}} = V\Delta Q\]
\[\Delta U_{\text{pot}} = -\frac{V}{\Delta Q}\]
MCQ
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Solution
The change in potential energy is \[\Delta U_{\text{pot}} = -V\Delta Q\]. The negative sign indicates that potential energy decreases as the charge moves through the potential difference.
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